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Simplify appservice login code (#8847)

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we don't need to support legacy login dictionaries here.
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Richard van der Hoff 2020-11-30 19:20:56 +00:00 committed by GitHub
parent 9f0f274fe0
commit 59e18a1333
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2 changed files with 22 additions and 6 deletions
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1
changelog.d/8847.misc Normal file
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@ -0,0 +1 @@
Simplify `uk.half-shot.msc2778.login.application_service` login handler.

27
synapse/rest/client/v1/login.py
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@ -154,13 +154,28 @@ class LoginRestServlet(RestServlet):
async def _do_appservice_login(
self, login_submission: JsonDict, appservice: ApplicationService
):
logger.info(
"Got appservice login request with identifier: %r",
login_submission.get("identifier"),
)
identifier = login_submission.get("identifier")
logger.info("Got appservice login request with identifier: %r", identifier)
identifier = convert_client_dict_legacy_fields_to_identifier(login_submission)
qualified_user_id = self._get_qualified_user_id(identifier)
if not isinstance(identifier, dict):
raise SynapseError(
400, "Invalid identifier in login submission", Codes.INVALID_PARAM
)
# this login flow only supports identifiers of type "m.id.user".
if identifier.get("type") != "m.id.user":
raise SynapseError(
400, "Unknown login identifier type", Codes.INVALID_PARAM
)
user = identifier.get("user")
if not isinstance(user, str):
raise SynapseError(400, "Invalid user in identifier", Codes.INVALID_PARAM)
if user.startswith("@"):
qualified_user_id = user
else:
qualified_user_id = UserID(user, self.hs.hostname).to_string()
if not appservice.is_interested_in_user(qualified_user_id):
raise LoginError(403, "Invalid access_token", errcode=Codes.FORBIDDEN)