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Speed up persisting large number of outliers (#16649)
Recalculating the roots tuple every iteration could be very expensive, so instead let's do a topological sort.
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4 changed files with 134 additions and 12 deletions
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changelog.d/16649.misc
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changelog.d/16649.misc
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Speed up persisting large number of outliers.
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@ -88,7 +88,7 @@ from synapse.types import (
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)
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from synapse.types.state import StateFilter
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from synapse.util.async_helpers import Linearizer, concurrently_execute
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from synapse.util.iterutils import batch_iter, partition
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from synapse.util.iterutils import batch_iter, partition, sorted_topologically_batched
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from synapse.util.retryutils import NotRetryingDestination
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from synapse.util.stringutils import shortstr
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@ -1669,14 +1669,13 @@ class FederationEventHandler:
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# XXX: it might be possible to kick this process off in parallel with fetching
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# the events.
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while event_map:
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# build a list of events whose auth events are not in the queue.
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roots = tuple(
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ev
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for ev in event_map.values()
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if not any(aid in event_map for aid in ev.auth_event_ids())
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)
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# We need to persist an event's auth events before the event.
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auth_graph = {
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ev: [event_map[e_id] for e_id in ev.auth_event_ids() if e_id in event_map]
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for ev in event_map.values()
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}
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for roots in sorted_topologically_batched(event_map.values(), auth_graph):
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if not roots:
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# if *none* of the remaining events are ready, that means
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# we have a loop. This either means a bug in our logic, or that
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@ -1698,9 +1697,6 @@ class FederationEventHandler:
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await self._auth_and_persist_outliers_inner(room_id, roots)
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for ev in roots:
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del event_map[ev.event_id]
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async def _auth_and_persist_outliers_inner(
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self, room_id: str, fetched_events: Collection[EventBase]
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) -> None:
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@ -135,3 +135,54 @@ def sorted_topologically(
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degree_map[edge] -= 1
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if degree_map[edge] == 0:
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heapq.heappush(zero_degree, edge)
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def sorted_topologically_batched(
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nodes: Iterable[T],
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graph: Mapping[T, Collection[T]],
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) -> Generator[Collection[T], None, None]:
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r"""Walk the graph topologically, returning batches of nodes where all nodes
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that references it have been previously returned.
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For example, given the following graph:
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A
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/ \
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B C
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\ /
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D
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This function will return: `[[A], [B, C], [D]]`.
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This function is useful for e.g. batch persisting events in an auth chain,
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where we can only persist an event if all its auth events have already been
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persisted.
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"""
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degree_map = {node: 0 for node in nodes}
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reverse_graph: Dict[T, Set[T]] = {}
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for node, edges in graph.items():
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if node not in degree_map:
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continue
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for edge in set(edges):
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if edge in degree_map:
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degree_map[node] += 1
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reverse_graph.setdefault(edge, set()).add(node)
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reverse_graph.setdefault(node, set())
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zero_degree = [node for node, degree in degree_map.items() if degree == 0]
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while zero_degree:
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new_zero_degree = []
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for node in zero_degree:
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for edge in reverse_graph.get(node, []):
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if edge in degree_map:
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degree_map[edge] -= 1
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if degree_map[edge] == 0:
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new_zero_degree.append(edge)
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yield zero_degree
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zero_degree = new_zero_degree
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@ -13,7 +13,11 @@
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# limitations under the License.
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from typing import Dict, Iterable, List, Sequence
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from synapse.util.iterutils import chunk_seq, sorted_topologically
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from synapse.util.iterutils import (
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chunk_seq,
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sorted_topologically,
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sorted_topologically_batched,
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)
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from tests.unittest import TestCase
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@ -107,3 +111,73 @@ class SortTopologically(TestCase):
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graph: Dict[int, List[int]] = {1: [], 2: [1], 3: [2], 4: [3, 2, 1]}
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self.assertEqual(list(sorted_topologically([4, 3, 2, 1], graph)), [1, 2, 3, 4])
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class SortTopologicallyBatched(TestCase):
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"Test cases for `sorted_topologically_batched`"
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def test_empty(self) -> None:
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"Test that an empty graph works correctly"
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graph: Dict[int, List[int]] = {}
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self.assertEqual(list(sorted_topologically_batched([], graph)), [])
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def test_handle_empty_graph(self) -> None:
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"Test that a graph where a node doesn't have an entry is treated as empty"
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graph: Dict[int, List[int]] = {}
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# For disconnected nodes the output is simply sorted.
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self.assertEqual(list(sorted_topologically_batched([1, 2], graph)), [[1, 2]])
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def test_disconnected(self) -> None:
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"Test that a graph with no edges work"
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graph: Dict[int, List[int]] = {1: [], 2: []}
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# For disconnected nodes the output is simply sorted.
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self.assertEqual(list(sorted_topologically_batched([1, 2], graph)), [[1, 2]])
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def test_linear(self) -> None:
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"Test that a simple `4 -> 3 -> 2 -> 1` graph works"
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graph: Dict[int, List[int]] = {1: [], 2: [1], 3: [2], 4: [3]}
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self.assertEqual(
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list(sorted_topologically_batched([4, 3, 2, 1], graph)),
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[[1], [2], [3], [4]],
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)
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def test_subset(self) -> None:
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"Test that only sorting a subset of the graph works"
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graph: Dict[int, List[int]] = {1: [], 2: [1], 3: [2], 4: [3]}
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self.assertEqual(list(sorted_topologically_batched([4, 3], graph)), [[3], [4]])
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def test_fork(self) -> None:
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"Test that a forked graph works"
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graph: Dict[int, List[int]] = {1: [], 2: [1], 3: [1], 4: [2, 3]}
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# Valid orderings are `[1, 3, 2, 4]` or `[1, 2, 3, 4]`, but we should
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# always get the same one.
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self.assertEqual(
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list(sorted_topologically_batched([4, 3, 2, 1], graph)), [[1], [2, 3], [4]]
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)
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def test_duplicates(self) -> None:
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"Test that a graph with duplicate edges work"
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graph: Dict[int, List[int]] = {1: [], 2: [1, 1], 3: [2, 2], 4: [3]}
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self.assertEqual(
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list(sorted_topologically_batched([4, 3, 2, 1], graph)),
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[[1], [2], [3], [4]],
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)
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def test_multiple_paths(self) -> None:
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"Test that a graph with multiple paths between two nodes work"
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graph: Dict[int, List[int]] = {1: [], 2: [1], 3: [2], 4: [3, 2, 1]}
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self.assertEqual(
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list(sorted_topologically_batched([4, 3, 2, 1], graph)),
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[[1], [2], [3], [4]],
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)
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