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hide RoomSubList if has 0 tiles and either searchFilter or emptyContent

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Signed-off-by: Michael Telatynski <7t3chguy@gmail.com>
This commit is contained in:
Michael Telatynski 2018-06-25 09:41:28 +01:00
parent 5b027c6410
commit a174555452
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GPG key ID: 3F879DA5AD802A5E
1 changed files with 10 additions and 3 deletions
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13
src/components/structures/RoomSubList.js
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@ -1,6 +1,7 @@
/*
Copyright 2017 Vector Creations Ltd
Copyright 2015, 2016 OpenMarket Ltd
Copyright 2017 Vector Creations Ltd
Copyright 2018 New Vector Ltd
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
@ -349,8 +350,14 @@ var RoomSubList = React.createClass({
var label = this.props.collapsed ? null : this.props.label;
let content;
if (this.state.sortedList.length === 0 && !this.props.searchFilter && this.props.extraTiles.length === 0) {
content = this.props.emptyContent;
if (this.state.sortedList.length === 0 && this.props.extraTiles.length === 0) {
// if no search filter is applied and there is a placeholder defined then show it, otherwise show nothing
if (!this.props.searchFilter && this.props.emptyContent) {
content = this.props.emptyContent;
} else {
// don't show an empty sublist
return null;
}
} else {
content = this.makeRoomTiles();
content.push(...this.props.extraTiles);