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Include rooms with 1 person invited

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If we can't find one with both people joined.
This commit is contained in:
David Baker 2016-08-02 15:55:18 +01:00
parent 3fc4e92a78
commit 61e0258b6f
1 changed files with 24 additions and 9 deletions
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33
src/components/views/rooms/MemberInfo.js
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@ -95,31 +95,31 @@ module.exports = React.createClass({
},
getExistingOneToOneRoomId: function() {
var self = this;
var rooms = MatrixClientPeg.get().getRooms();
var userIds = [
const rooms = MatrixClientPeg.get().getRooms();
const userIds = [
this.props.member.userId,
MatrixClientPeg.get().credentials.userId
];
var existingRoomId;
let existingRoomId = null;
let invitedRoomId = null;
// roomId can be null here because of a hack in MatrixChat.onUserClick where we
// abuse this to view users rather than room members.
var currentMembers;
let currentMembers;
if (this.props.member.roomId) {
var currentRoom = MatrixClientPeg.get().getRoom(this.props.member.roomId);
const currentRoom = MatrixClientPeg.get().getRoom(this.props.member.roomId);
currentMembers = currentRoom.getJoinedMembers();
}
// reuse the first private 1:1 we find
existingRoomId = null;
for (var i = 0; i < rooms.length; i++) {
for (let i = 0; i < rooms.length; i++) {
// don't try to reuse public 1:1 rooms
var join_rules = rooms[i].currentState.getStateEvents("m.room.join_rules", '');
const join_rules = rooms[i].currentState.getStateEvents("m.room.join_rules", '');
if (join_rules && join_rules.getContent().join_rule === 'public') continue;
var members = rooms[i].getJoinedMembers();
const members = rooms[i].getJoinedMembers();
if (members.length === 2 &&
userIds.indexOf(members[0].userId) !== -1 &&
userIds.indexOf(members[1].userId) !== -1)
@ -127,6 +127,21 @@ module.exports = React.createClass({
existingRoomId = rooms[i].roomId;
break;
}
const invited = rooms[i].getMembersWithMembership('invite');
if (members.length === 1 &&
invited.length === 1 &&
userIds.indexOf(members[0].userId) !== -1 &&
userIds.indexOf(invited[0].userId) !== -1) &&
invitedRoomId === null
{
invitedRoomId = rooms[i].roomId;
// keep looking: we'll use this one if there's nothing better
}
}
if (existingRoomId === null) {
existingRoomId = invitedRoomId;
}
return existingRoomId;